A number consists of two digits whose sum is five.when the digits are reversed,the number becomes greater by nine.find the number
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Let the number be 10t+u where t is the tens and u is the units digit.
Equations:
t + u = 5
10u+t = 10t+u +9
Simplify :
t + u = 5
9u - 9t = 9
t + u = 5
-t+u = 9
Add:
2u = 14
u = 7
But, if u = 7, then t= -2
and that makes no sense
for a 2-digit number.
Equations:
t + u = 5
10u+t = 10t+u +9
Simplify :
t + u = 5
9u - 9t = 9
t + u = 5
-t+u = 9
Add:
2u = 14
u = 7
But, if u = 7, then t= -2
and that makes no sense
for a 2-digit number.
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