Question

A number consists of two digits whose sum of digits is 12.If the new number obtained by reversing the digits is greater than the original number by 18 find the original number

Answer 1

ORIGINAL ANSWER IS 57

Let unit place is x and tenth place is y so

Condition 1

x +y = 12

Condition 2 if digit reversed

y +10x = x + 10y -18

y + 10x -x - 10y= -18

9x -9y = -18

9y -9x =18

9y- 9(12–y)= 18

9y-108+9y=18

18y= 18+108

y = 126/18

y= 7

So x = 12–7 =5

Original number = 10x +y = 10x5+7= 57

Answer 2

Hope it helps you

Please mark me as the brainliest