Question

a number consists of two whose sum is 9 if 27 is subtracted from the number its digits are reversed. Find the number​

Answer 1

If you keep x as the ten's digit of the original number and y as the unit's digit of the number , any number following : x 3=y , will follow this rule . The numbers following this rule is 14 27=41 , 25 27=52 , 36 27=63 , 47 27=74 , 58 27=85 , 69 27=96

Answer 2

Answer:

Given:-

• let ones place digit of a number = x

• Sum of 2 digits = 9

• Tens place digit of a number = 9 - x

Step-by-step explanation:

Then:-

➤ 10 ( 9 - x ) x = 90 - 10x - x

= 90 - 9x

Now:-

• 27 is subtracted from the number we get the digits are reversed.

Solution:-

➠ 90 - 9x - 27 = 10 (x) + 9 - x

➠ 90 - 9x - 27 = 10x + 9 - x

➠ - 9x + 63 = 9x + 9

➠ 63 - 9 = 9x + 9x

➠ 54 = 18x

➠ $\bf \frac{54}{18} = x$

➠ x = 3

$\therefore therefore$

⇒ Ones place = 3

⇒ Tens place = 9 - 3

= 6.

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