Question

A number consits of two digits of which tens exceeds the unit digit by 7 .the number itself is eqal to the sum of its dogits .the number is

Answer 1

Answer:

let unit digit be x,

tens  digit = x+7

then value no:

10(x+7)+x;

10x+70+x;

11x+70;

ten times sum of digits

10(x+x+7);

10(2x+7);

20x+70;

according to question 

20x+70=11x+70;

20x-11x=70-70;

9x=0,

x=0

therefore unit digit = 0

tens digit=0+7

therefore no. =70

Answer 2

Answer:

Step-by-step explanation:

Let the number is 10y+x where x is the unit digit and y is the ten's digit. Then by the given question,

y=x+6 -------------(1) and

10y+x=10(x+y)

or, 10y+x=10x+10y

or, x-10x=0

or, x=0

 ∴, y=0+6

or, y=6

∴, the given number is 

10×6+0=60