Question

a number consots of two digits whose sum is 9 if 27 is subrated from the number it's digits are reversed find the number​

Answer 1

✬ Number = 63 ✬

Step-by-step explanation:

Given:

• Sum of two digits of a number is 9.
• After subtracting 27 from the number digits get reversed.

To Find:

• What is the number ?

Solution: Let the tens digit be x and ones digit be y. Therefore, number is 10x + y

➟ (Tens + Ones) digit = 9

➟ x + y = 9

➟ x = 9 – y......(eqⁿ 1)

[ After reversing digits new number formed is]

• Reversed number = (10y + x)

A/q

• After subtracting 27 from the number digits get reversed.

$\implies{\rm }$ 10x + y – 27 = 10y + x

$\implies{\rm }$ 10x – x + y – 10y = 27

$\implies{\rm }$ 9x – 9y = 27

$\implies{\rm }$ 9(x – y) = 27

$\implies{\rm }$ 9 – y – y = 27/9

$\implies{\rm }$ 9 – 2y = 3

$\implies{\rm }$ 9 – 3 = 2y

$\implies{\rm }$ 6/2 = y

$\implies{\rm }$ 3 = y

So digits of number are

➬ Ones digit is y = 3

➬ Tens digit is 9 – 3 = 6

Hence, original number is 10(6) + 3 = 63

[ Verification ]

➬ Original no. – 27 = Reversed number

➬ 63 – 27 = 36

➬ 36 = 36

$\large\bold{\texttt {Verified }}$

Answer 2

Correct Question :-

A number consists of two digits whose sum is 9. If 27 is subtracted from the number, It's digits are reversed. Find the number.

Solution :-

☯️ Let,

The One's Digit = x.

The Ten's Digit = y.

As Per Question,

x + y = 9.

We Can Say,

x = 9 - y.

Original Number,

10x + y.

And, Reversed Number,

10y + x.

Now, According To Question,

➙ 10x + y - 27 = 10y + x.

➙ 9x - 9y = 27.

➙ 9(x - y) = 27.

➙ x - y = 3.

➙ 9 - y - y = 3.

➙ 9 - 2y = 3.

➙ 2y = 6.

➙ y = 3.

Now,

• One's Digit = x = 9 - y = 6.

• Ten's Digit = y = 3.

Hence, Original Number = 36.