Question

A number cube has it side numbers as 12467 and 5 if the wine is thrown once what is probility of rolling an odd no​

Answer 1

Answer:

$\frac{1}{2}$

Step-by-step explanation:

P(E)=$\frac{No. of possible outcomes}{Total no. of outcomes}$

possible outcomes =1;7;5

No. of possible outcomes =3

total no. of outcomes = 6

P(odd no.) = $\frac{3}{6}$

                 =$\frac{1}{2}$