a number decreased by 10% then increased 10%. the number so obtained is less than the originam number. what was the original number
K123krishna:
rewrite the question because the difference b/n new no. and original number is not given
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let the number be x
it is decreased by 10%
so new number x'=x-10x/100
x'=x-0.1x
x'=0.9x
so now number is increased by 10%
x'=0.9x+0.9x*10/100
x'=0.9x+0.09x
x'=0.99x
hence new number is 0.99 times the original number
hope this helps
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