Question

A number devided by 5 and 9 leaves remainder4 and 3.What will be remainder when it devided by 45

Answer 1

Answer:21

Step-by-step explanation:

Let the number = N

N = 5p + 1 - Since the number when divided by 5 gives remainder 1.

In successive division, the quotient from 1st division is divided by second number.

Now p can be written as 9q + 4 since p divided by 9 gives remainder of 4

Therefore, original number can be written as :

N = 5(9q + 4) + 1

= 45q + 20 + 1

= 45q + 21

If this number is divided by 45, Remainder = 21