Question

a number exceeds 20% of itself by 40 find the number

Answer 1

let number be x
x/5+40=x
4x/5=40
x=40*5/4
x=50

Answer 2

Hello,
let the number be n.
we have that:
n=20% of n+40
or:
n=20/100n+40;
n-20/100n=40;
100n-20n/100=40;
80n/100=40;
4n/5=40;
4n=40×5;
4n=200;
n=200:4=50

hence the number is 50.

bye :-)