A number exceeds 30% of itself by 70, find the number. *
Answers
Answered by
0
Answer:
Now, represent the statement in mathematical format(aptitude questions are much easier to solve in math representation rather than as statements)..
So, The question says..our number, ‘x’ is just 40 more than 20% of ‘x’
Now, 20% of ‘x’ in mathematical representation is…(20/100)*x
Now, (20/100)*x is equal to 0.2*x (since 20/100=2/10 which is 0.2)
So, now, we write our original statement of ‘x’ being 40 more than 20% of itself…
x=(0.2*x)+40
x-(0.2*x)=40
x-0.2x=40
0.8x=40 (since,1–0.2=0.8)
x=40/0.8
x=50
So, our answer is 50
Answered by
0
Correct option is B)
Solution:-
Let the no. be x.
∴20% of x=
100
20
×x=
5
x
Given that the number exceeds 20% of itself by 40.
∴x−
5
x
=40
⇒
5
4x
=40
⇒x=40×
4
5
⇒x=50
Hence, the correct answer is 50.
Hope it helped
Solution:-
Let the no. be x.
∴20% of x=
100
20
×x=
5
x
Given that the number exceeds 20% of itself by 40.
∴x−
5
x
=40
⇒
5
4x
=40
⇒x=40×
4
5
⇒x=50
Hence, the correct answer is 50.
Hope it helped
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