A number exceeds four times its reciprocal by 3. Find the number.
Can someone help me in this..
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Answers
Answered by
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Let the number be x......
Then, it's reciprocal is 1/x...
Acc. to ques,
x-4/x=3
=>x²-4=3x
=>x²-3x-4=0
=>x²-4x+x-4=0
=>x(x-4)+1(x-4)=0
=>(x-4)(x+1)=0
=>x=4,-1
Hence the two numbers are 4,-1
Then, it's reciprocal is 1/x...
Acc. to ques,
x-4/x=3
=>x²-4=3x
=>x²-3x-4=0
=>x²-4x+x-4=0
=>x(x-4)+1(x-4)=0
=>(x-4)(x+1)=0
=>x=4,-1
Hence the two numbers are 4,-1
nidhi110:
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Answered by
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hye
========================================
let the number be x
=>A number exceeds four times its reciprocal by 3.
=>so let us form an euqation
=> x = 4 +3
=>x = +3
=>x = '
=>x² = 4 +3x
=> x² -3x -4 = 0
=>x² - 4x +x - 4 = 0
=>(x-4)(x+1)=0
=>∴ x = -1 and 4
=====================================
hope it helps u........
========================================
let the number be x
=>A number exceeds four times its reciprocal by 3.
=>so let us form an euqation
=> x = 4 +3
=>x = +3
=>x = '
=>x² = 4 +3x
=> x² -3x -4 = 0
=>x² - 4x +x - 4 = 0
=>(x-4)(x+1)=0
=>∴ x = -1 and 4
=====================================
hope it helps u........
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