A number exceeds the other number by 12. If their sum is 72, find the numbers.
Answers
Answer:
let the unknown numbers be x and y.
a/q
x = y + 12 ..... i)
and
x + y = 72
⇒ x = 72 - y. ..... ii)
on substituting value of x in equation 1, we get
72 - y = y + 12
⇒ 72 - 12 = 2y
⇒ y = 60/2
∴ y = 30
by placing value of y in ii), we get
x = 72 - 30
∴ x = 42
so, the numbers required are 42 and 30.
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MrBrainliestV Ace
Answer:
Step-by-step explanation:
Given :-
A number exceeds other number by 12.
Their sum is 72.
To Find :-
The Numbers.
Solution :-
Let the 1st number be x.
And the 2nd number be x + 12
According to the question
x + x + 12 = 72
⇒ 2x + 12 = 72
⇒ 2x = 72 – 12
⇒ 2x = 60
⇒ x = 30
1st Number = 30
2nd Number = 30 + 12 = 42
Hence, the numbers are 30 and 42.
Step-by-step explanation:
Hope its help you
Answer:
30
Step-by-step explanation:
let the number =x
second number=x+12
x+x+12=72
2x+12=72
2x=72-12=60
2x=60
x=60/2
x=30