A number exceeds the other number by 12. If their sum is 72, find the numbers.
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Answer:
1st number = x
2nd number = (x + 12)
Sum of numbers = 72
x + (x + 12) = 72
x + x + 12 = 72
2x + 12 = 72
2x = 72 - 12
2x = 60
x = 60 ÷ 2
x = 30
Hence, 1st number = x
= 30
2nd number = x + 12
= 30 + 12
= 42
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