Question

A number from 1 to 10 is chosen at random. Find the probability of choosing,

a) the prime number. b) the number greater than 10​

Answer 1

The numebers chosen are from 1 to 10.

Then possible outcomes are: 1,2,3,4,5,6,7,8,9,10

The probability of chosen a 5  OR and even number = probability of chosen a 5  + probability of chosen an even number.

Let us calculate each event:

P ( 5) = 1/10

Even number are: 2,4,6,8,10

==> P(even) = 5/10

Then :

P( 5 OR even) = P(5) + P(even)

                      = 1/10 + 5/10 = 6/10

                      = 3/5

==> P ( 5 or even) = 3/5

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Answer 2

Step-by-step explanation:

total numbers are 10,

so total possible outcome = 10

now,

1)

the event A can be noted as the choosing the number which is prime,

here favourable outcomes = 1,2,3,5,7

numbers = 5

so P(A) = favourable out come/ total outcome

P(A) = 5/10

P(A) = 1/2

2)

event B is number is greater than 10,

here there is no number is greater than 10

so,

favourable out come is 0

so,

P(A) = 0/10

P(A) = 0

(impossible event, so probability is zero)

hope this will help you.

Thank you

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