Question

a number has 2 digits the units digit is 3 times the tens digit if the difference between the number obtains by reversing the digits is 36 find the original number​

Answer 1

Answer:

LET NUMBER AT TENS PLACE BE X

NUMBER AT ONES PLACE 3X

NO. =10X+3X≠13X

AFTER INTERCHANGING THE NUMBERS

NUMBER AT TENS PLACE 3X

NUMBER AT ONES PLACE X

NO. 3X+10+X=31X

The difference between the number and the number obtained by reversing the digit is 36

ATQ. 13X-31X=36

-18X=36

X=-36/18=-2

13X=-2*13=-26

SO THE NUMBER IS -26