Question

a number has 2-digits. the units digit of the number is 3 times the ten's digit. if the digits are reversed, the new number thus formed, is 36 more than the original number. find the original number.

Answer 1

Let Number be 10x+y where x = tens digit and y = unit place digit
Now given,
units digit of the number is 3 times the ten's digit
Therefore y = 3x
Lets now reverse the number the number thus formed will be 10y+x

Now,
the new number thus formed, is 36 more than the original number

ATQ,
10y+x - (10x+y) = 36
9y-9x = 36
y-x = 4
now putting y = 3x
3x-x = 4
2x = 4
x = 2
y = 6

Therefore the original number is 2×10+6 = 26