Question

A number has 3 digits whose sum is 17. the middle one exceeds the sum of other two by 1

Answer 1

1 + 9 + 7 = 17
2 + 9 + 6 = 17
3 + 9 + 5 = 17
4 + 9 + 4 = 17
5 + 9 + 3 = 17
6 + 9 + 2 = 17
7 + 9 + 1 = 17
Therefore, the numbers are 197, 296, 395, 494, 593, 692 & 791.