Question

a number has 4 digits. its last digit is twice the first. its 2nd digit is three less than the third digit which is 6. but if u add the last digit to first the answer will be 12.what is the number

Answer 1

let the first digit be x.
last digit will be 2x.
sum of first and last digit is 12.

2x + x = 12
3x = 12
x = 4
then, first number be 4 and last number be 8.
the second no. is 3 less than third no.
Third no.= 6
second no.=6-3=3
then,number is 4368

Answer 2

The answer is 4368
Since it's last digit is twice the first
Therefore,
Last digit = 2(First digit)
Also,
If we add the last digit to first, then the answer is 12
Therefore,
Last digit + First digit = 12
But since last digit is equal to 2 times of first digit
Therefore, 2(First digit)+ First digit = 12
3(First digit) = 12
First digit = 12/3
First digit = 4
This implies Last digit is 8
Now,
Since its 2nd digit is 3 less than the 3rd digit which is 6
Therefore,
2nd digit + 3 = 6
2nd digit = 6-3
2nd digit = 3

Hence the answer is 4368
HOPE IT HELPS ( ͡° ͜ʖ ͡°)