A number has two digit the digit at ten place is four times the digit at unit place if 54 is subtracted from the number the digits are reversed find the number
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Step-by-step explanation:
Let the one's place be y and tens digit be x.
then, Number = 10x + y.
∴ Given, (x) = 2y ∴5x=2y⋯(i)
But, if 18 is subtracted, then, number gets reversed
ie. 10y + x.
∴(10x+y)−18=10y+x
⇒10x+y−18=10y+x
⇒10x−x+y−10y−18=0
⇒9x−9y−18=0
⇒x−y−2=0 Putting [y= 2 5x ]
⇒x− 2 5x−2=0
⇒2x−x−2=0 ∴y= 2x
y = 1
⇒x=2
number is 21
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