a number has two digit ,whose sum is 9 if 27 subtracted from the number its digit are reserved find the number
Ram1993:
63
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1
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no it is wrong...the number is 63
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Let the two digit number be 10x + y
Sum of the digits = 9
⇒ x + y = 9 (Equation - 1)
If 27 subtracted from this number the digits are interchanged.
Therefore
10x + y - 27 = 10y + x
10x - x + y - 10 y = 27
9x - 9y = 27
Taking 9 as common
x - y = 3 (Equation-2)
Taking both equations as simultaneous equation
Adding 1 and 2 equations
x + y = 9
x - y = 3
2x = 12
x = 6
6+y = 9
y = 3
The number is 10x + y = 10(6) + 3 = 63
Sum of the digits = 9
⇒ x + y = 9 (Equation - 1)
If 27 subtracted from this number the digits are interchanged.
Therefore
10x + y - 27 = 10y + x
10x - x + y - 10 y = 27
9x - 9y = 27
Taking 9 as common
x - y = 3 (Equation-2)
Taking both equations as simultaneous equation
Adding 1 and 2 equations
x + y = 9
x - y = 3
2x = 12
x = 6
6+y = 9
y = 3
The number is 10x + y = 10(6) + 3 = 63
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