Question

a number has two digits the digit at ten place is four times the digit at unit place if 54 is subtaracted from the number the digits are reversed find the number​

Answer 1

Solution :-

Given : A number has two digits the digit at ten place is four times the digit at unit place.

Let the digit of unit place be x

Digit of ten place = 4x

Number = 4x × 10 + x

When the digit of number reversed = x × 10 + 4x

According to the question,

=> (4x × 10 + x) - 54 = x × 10 + 4x

=> 40x + x - 54 = 10x + 4x

=> 41x - 14x = 54

=> 27x = 54

=> x = 54/27 = 2

Therefore,

Number = 4x × 10 + x

= 4 × 2 × 10 + 2

= 80 + 2 = 82

Hence,

The number = 82

Answer 2

$\huge\textbf{Answer:-}$

• Let y be the digit of unit place.

• Let 4y be the Digit of ten place 4y × 10 + y is the Number.

• It will be x × 10 + 4x when the digit is reversed.

From the question:-

⇒(4y × 10 + y) - 54 = y × 10 + 4y

⇒40y + y - 54 = 10y + 4y

⇒41y - 14x = 54

⇒27y = 54y = 54/27 = 2

So,

⇒4y × 10 + y4 × 2 × 10 + 2

⇒80 + 2 = 82

Therefore, 82 is the Number

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