Math, asked by LearnerNambi, 1 year ago

A number has two digits. The digit at ten's place is 4 times the digit at unit's place. If 54 is subtracted from the number, the digits are reversed. What is the number?​

Answers

Answered by archnakri2007
13

Question:

____________

A number has two digits. The digit at ten's place is 4 times the digit at unit's place. If 54 is subtracted from the number, the digits are reversed. What is the number?

Answer:

__________

82

Explanation:

_______________

Let the digit at the unit place be x.

Hence, digit at ten's place = 4 × x = 4x

The number = 10 × 4x + x = 40x + x = 41x

But, when it's digits are reversed , then -

Unit place = 4x

Ten's place = x

Hence, The Number formed = 10x + 4x = 14x

A/q,

41x - 54 = 14x

=> 41x - 14x = 54

=> 27x = 54

=> x = 54/27

=> x = 2

Now,

Unit place = x = 2

Ten's place = 4x = 4 × 2 = 8

Then,

The number = 8 × 10 + 2 = 80 + 2 = 82

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