A number has two digits. The digit at ten's place is 4 times the digit at unit's place. If 54 is subtracted from the number, the digits are reversed. What is the number?
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Question:
____________
A number has two digits. The digit at ten's place is 4 times the digit at unit's place. If 54 is subtracted from the number, the digits are reversed. What is the number?
Answer:
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82
Explanation:
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Let the digit at the unit place be x.
Hence, digit at ten's place = 4 × x = 4x
The number = 10 × 4x + x = 40x + x = 41x
But, when it's digits are reversed , then -
Unit place = 4x
Ten's place = x
Hence, The Number formed = 10x + 4x = 14x
A/q,
41x - 54 = 14x
=> 41x - 14x = 54
=> 27x = 54
=> x = 54/27
=> x = 2
Now,
Unit place = x = 2
Ten's place = 4x = 4 × 2 = 8
Then,
The number = 8 × 10 + 2 = 80 + 2 = 82
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