A number has two digits the digit at tens place is four times the digits at unit place if 54 is subtracted from the number the digits are reversed find the number
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- ACCORDING TO THE QUESTION :-
x = 3y ... eq. 01
- According to the second condition :
10x + y - 54 = 10y + x
=> 9x - 9y = 54
=> 9(x - y) = 9 × 6
=> x - y = 6 ... eq.02
- Now we can solve the Equation 01 and 02 by substitution Method :-
x - y = 6
=> 3y - y = 6 [ from eq.01 , x = 3y ]
=> 2y = 6
=> y = 3
- Now we can substitute the value of y in eq. 01 to get value of x
x = 3y
=> x = 3 × 3
=> x = 9
Hence the number is
Hence the number is 10x + y = 90 + 3 = 93
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