Question

a number has two digits the ones digit is one fourth of tens digit the difference between the number and the new number obtained by reversing its digit is 54 find the original number​

Answer 1

Answer:

82

Step-by-step explanation:

let the no at once place be x

no at tens place will be 4x

10(4x) + x = some no (y)

41x = y

in second case

10 (x) + 4x = any no (z)

14x = z

AtQ

y-z = 54

41x-14x = 54

27x = 54

x = 2

at the once place = 2

at the tens 4x = 8

so the no is 82....

Note: it hard to understand these type of question from the written text........ask to teacher.