Math, asked by anshikamaheshwari06, 11 months ago

A number has two digits the unit digit is three times the tens digits. The difference between the number and the number obtained by reversing the digit is 36. Find the original number.​

Answers

Answered by rajeshkumar822
6

Step-by-step explanation:

let the number at tens place be x

number at ones place 3x

number =10*tens digit +ones digit

10*x+3x

=13x

AFTER INTERCHANGING THE NUMBERS

number at tens place 3x

number at ones place x

Number 10*3x+x=31x

The difference between the number and the number obtained by reversing the digit is 36.

ATQ. 13X-31X=36

-18X=36

X=-36/18=-2

NUMBER AT TENS PLACE = -2

NUMBER AT ONES PLACE =-6

NUMBER =-20-6=-26

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