A number has two digits the unit digit is three times the tens digits. The difference between the number and the number obtained by reversing the digit is 36. Find the original number.
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Step-by-step explanation:
let the number at tens place be x
number at ones place 3x
number =10*tens digit +ones digit
10*x+3x
=13x
AFTER INTERCHANGING THE NUMBERS
number at tens place 3x
number at ones place x
Number 10*3x+x=31x
The difference between the number and the number obtained by reversing the digit is 36.
ATQ. 13X-31X=36
-18X=36
X=-36/18=-2
NUMBER AT TENS PLACE = -2
NUMBER AT ONES PLACE =-6
NUMBER =-20-6=-26
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