Question

A number has two digits. The units digit is 3 times the tens digit.If the digits are reversed, the new number thus formed is 36 more than the original number. Find the original number.

Answer 1

Let Number be 10x+y where x = tens digit

and y = unit place digit

Now given,

units digit of the number is 3 times the

ten's digit

Therefore y = 3x

Lets now reverse the number the number

thus formed will be 10y+x

Now,

the new number thus formed, is 36 more

than the original number

ATQ,

10y+x - (10x+y) = 36

9y-9x = 36

y-x = 4

now putting y = 3x

3x-X = 4

2x = 4

x = 2

y = 6

Therefore the original number is 2x10+6

= 26

Hope this helps.....

Answer 2

Answer:

the upper answer is correct and explanation also