Question

A number has two digits whose sum is 8 if 36 is added to the number it's digits get inter changed find the number

Answer 1

Solution :-

Let us assume x and y are the two digits of the number

Therefore, two-digit number is = 10x + y and the reversed

number is 10y + x

Given:

x + y = 8

x = 8 – y --------------1

Also given:

10x + y + 36 = 10y + x

9y – 9x = 36

y – x = 4 --------------2

Substitute the value of x from eqn 1 in eqn 2

y – (8 – y) = 4

2y – 8 = 4

2y = 12

y = 6

Therefore, x = 8 – y = 8 – 6 = 2

Therefore, two-digit number = 10x + y = (10 * 2) + 6 = 26

and the reversed number = 10y + x = (10 * 6) + 2 = 62

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