Question

A number has two digits, whose sum is 9. If 27 is added to the number, its digits get inerchanged. Find
the numbers

Answer 1

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Answer:

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Let the two numbers be a,b.

So, The two digit number will be 10a + b, and reverse of that number = 10b + a

                                                                             

                                                                                                

Given, a + b =9                   -------------------  (i)

           10a + b - 27 = 10b + a

           a - b = 3                   --------------------  (ii)

On solving (i) and (ii), we get

    a = 6

Submit this value in (ii) on we get,

          b = 9 - 6 = 3

On submitting the value in above equation we get,

10a + b

= 10 * 6 + 3

=63

So, The number is 63.

Hope it helps you ✌️✌️❤️❤️

Answer 2

Let one digit be x
Do other digit is 9 - x
Tens. Ones Number
Original 10(9-x) x 90-10x+x=90-9x

Reversed 10x 9-x. 10x+9-x=9x+9

90-9x+27=9x+9
117-9=18x
108= 18x
108/18=x
6= x

So original no=10(9-6)+6=36
New no=10(6) +9-6=63
Hope this helps