a number has two digits whose sum is 9 if 27 is added to the number its digits get interchanged
find the number
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Let the two numbers be a,b.
So, The two digit number will be 10a + b, and reverse of that number = 10b + a
Given, a + b =9 ------------------- (i)
10a + b - 27 = 10b + a
a - b = 3 -------------------- (ii)
On solving (i) and (ii), we get
a = 6
Submit this value in (ii) on we get,
b = 9 - 6 = 3
On submitting the value in above equation we get,
10a + b
= 10 * 6 + 3
=63
So, The number is 63.
Hope this helps!
So, The two digit number will be 10a + b, and reverse of that number = 10b + a
Given, a + b =9 ------------------- (i)
10a + b - 27 = 10b + a
a - b = 3 -------------------- (ii)
On solving (i) and (ii), we get
a = 6
Submit this value in (ii) on we get,
b = 9 - 6 = 3
On submitting the value in above equation we get,
10a + b
= 10 * 6 + 3
=63
So, The number is 63.
Hope this helps!
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