A number is 106r is divisible by 6.what is the value of r?
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Answer:
The least value of r is 2
Step-by-step explanation:
The divisibility rule of 6 is the number should be divisible by both 2 and 3.
By Hit and Trial,
1061 it is not divisible by 2
1062 it is divisible by 2 because unit digit is 2.
It is divisible by 3 also because sum = 1+6+0+2 = 9.
So the least value of r is 2
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