A number is 2/5 times another number if their sum is 70 find the other number
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A number is 2/5 times second number. If their sum is 70, find the numbers.
Let the second number be 'x'.
Then, first number is 2/5 times the second number.
=> first number
= 2/5 × x
= 2x/5
Now, their sum
= x + (2x/5)
= (5x+2x)/5
= 7x/5
But, their sum is 70 (According to Question)
Then,
7x/5 = 70
=> x = 70 × 5/7
=> x = 10 × 5
=> x = 50
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Thank you. ;-)
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