Question

a number is 20 less than 10 times of the average of its fifth, quarter and one-fourteenth. find 2/9 of the number​

Answer 1

The required result is $-\frac{254}{63}$

Step-by-step explanation:

Let the number be 'x'.

The average of its fifth, quarter and one-fourteenth is given by,

$\frac{\frac{1}{5}+\frac{1}{4}+\frac{1}{14}}{3}$

A number is 20 less than 10 times of the average of its fifth, quarter and one-fourteenth is given by,

$x=10(\frac{\frac{1}{5}+\frac{1}{4}+\frac{1}{14}}{3})-20$

Solving the equation,

$x=10(\frac{\frac{56+70+20}{280}}{3})-20$

$x=10(\frac{\frac{146}{280}}{3})-20$

$x=10(\frac{146}{280\times 3})-20$

$x=10(\frac{146}{840})-20$

$x=\frac{13}{7}-20$

$x=\frac{13-140}{7}$

$x=\frac{-127}{7}$

Now, $\frac{2}{9}$ of the number is

$\frac{2}{9}\times \frac{-127}{7}=-\frac{254}{63}$

Therefore, the required result is $-\frac{254}{63}$

#Learn more

One fifth of a number is 20 less than the number find the number.

https://brainly.in/question/2245676

Answer 2

Answer:

Answer is 320

#Solved at home

Aditya Jha