Math, asked by lenkabirakishore, 11 months ago

A number is 4 times another number, If
21 is added to both the numbers then first
number becomes 7/4 times the other
number. What are the numbers?​

Answers

Answered by EliteSoul
60

Answer:

\large{\underline{\boxed{\mathfrak\blue{Numbers = 7 \: and \: 28 }}}}

Given:-

  • 1st number = 4 × 2nd number
  • If 21 added to both numbers,1st number = 7/4 × 2nd number.

To find:-

  • What are the numbers?

Let the 2nd number be y.

\therefore 1st number = 4y.

A/Q,

  • 21 addedto both numbers,1st number = 7/4 times 2nd number.

\twoheadrightarrow\sf 4y + 21 = \dfrac{7}{4}\times (y + 21)\\\\ \twoheadrightarrow\sf 4y + 21 = \dfrac{7(y + 21)}{4} \\\\ \twoheadrightarrow\sf  4(4y + 21) = 7y + 147 \\\\ \twoheadrightarrow\sf 16y + 84 = 7y + 147 \\\\\twoheadrightarrow\sf 16y - 7y = 147 - 84 \\\\\twoheadrightarrow\sf 9y = 63 \\\\ \twoheadrightarrow\sf y = 63/9 \\\\ \twoheadrightarrow\large{\underline{\boxed{\sf\blue{y = 7 }}}}

\rule{100}2

\star \: \: \sf 1st \: number = 4y = 4(7) = \large{\boxed{\sf\red{28}}}

\star \: \: \sf 2nd \: number = y = \large{\boxed{\sf\green{7}}}

\therefore{\underline{\text{Numbers = 28 \: \& \: 7 \: respectively }}}

Answered by Anonymous
17

 \red{Let  \: the \:  numbers \:  be \:  x  \: and \:  y.}

{x=4y …(1)}

 \blue{acc. \: to \: the \: que.}

(21+x)/(y+21) = 7/4  \:

=>4(21+x) = 7(y+21)  \:

 \: =>84 + 4x = 7y +147

  \bf{=16y - 7y=147 - 84}

=>9y=63 \:

 \: =>y=7

 \purple{now. \: putting \: the \: value \: of \: y}

x = 4y = 4 \times 7 = 28

</p><p> \pink{y = 7 } \orange{and } \:  \green {x = 28.}</p><p></p><p>

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