Question

a number is 4 times the other number. if their product is 80, what are the numbers?​

Answer 1

$Let \; the \; first \; no. \; be \; x. \\</p><p>Then, \; the \; other \; no. = 4×x = 4x$

$\large \bold {A/q}$

$\implies x×4x = 80$

$\implies 4x² = 80$

$\implies x² = \Large \frac{80}{4}$

$\implies x² = 20$

$\implies x = √20$

$\implies x = 2√5$

$So, \; the \; first \; no. = 2√5 \\</p><p>\& \; the \; second \; no. = 4×2√5 = 8√5$

Answer 2

Answer:

number is 2√5

Step-by-step explanation:

4x*x = 80

4x^2 = 80

x^2 = 80/4

x^2 = 20

x= √20.

x = 2√5