Question

a number is 42 more than the average of its half, one-third, one-fifteenth. find the number​

Answer 1

Answer:

Let the number be X

So according to condition

Half of the number is X/2

One third of the number is X/3

One sixth of the number is X/6

Average of all three numbers will be

=> (X/2+ X/3+ X/6)/3 = X/3

And number is 6 more than the average, so

=> X= 6+X/3

=> 2X/3 = 6

=> X= 9

Hence the number is 9

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