a number is 5/8 times another if there sum is 104 find the numbers
Answers
Answered by
39
Hey
Let the original number be x .
Second number =
5 / 8 times the first number
= 5x / 8 .
So,
Their sum is =
x + 5x /8 = 104
=> 8x + 5x / 8 = 104
=> 13x = 104 * 8
=> x = 104 * 8 / 13
=> x = 8 * 8
=> x = 64
So first number = 64
Second number = 5 / 8 * 64
= 5 * 8
= 40 .
thanks :)
Let the original number be x .
Second number =
5 / 8 times the first number
= 5x / 8 .
So,
Their sum is =
x + 5x /8 = 104
=> 8x + 5x / 8 = 104
=> 13x = 104 * 8
=> x = 104 * 8 / 13
=> x = 8 * 8
=> x = 64
So first number = 64
Second number = 5 / 8 * 64
= 5 * 8
= 40 .
thanks :)
Answered by
6
Answer:
Let the number be x
= 5/8x = 104
8+5=104
13x=104
x= 104/13
x=8
x= 8×8
x=64
So, the first number is x=64 & the another number be 5/8×64 = 40
Step-by-step explanation:
Hope this will help you
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