Question

A number is 5\8 times another number.If their sum is 104,find the numbers

Answer 1

let no.=x
then ,
x+5/8x=104
13x=104×8
x=104×8/13
x=8×8
x=64
so,
first no. is x=64
and another is 5/8times of first no.=5/8x
5/8×64=40

Answer 2

The two numbers are x=40, y=64

Let's call the first number x and the second number y. We know from the problem statement that:

$x = 5/8 * y$

We also know that the sum of x and y is 104. So we can write:

x + y = 104

Now we have a system of two equations with two variables (x and y). We can use substitution method to solve this system. We'll substitute the value of x in the second equation with the expression from the first equation:

$(5/8 * y) + y = 104$

Now we can solve for y:

$y = 104 / (1 + 5/8) = 104 * 8/13 = 64$

Now we can use this value of y to find x

$x = 5/8 * y = 5/8 * 64 = 40$

So the two numbers are x=40, y=64

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