A number is 5/8 times another number if their sum is 104 find the number?
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Step-by-step explanation:
Let the second number be X.
First number = (5/8) X
Given, X + (5/8) X = 104
(8X + 5X) / 8 = 104
13X = 104 x 8
X = 8 x 8 = 64
So, one number = 64
Another number = (5/8) x 64 = 40
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