A number is 56 greater than the average of it's third,quarter and one-twelfth.find it.
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let the no be x
according to the question equation so formed is
x - [(x/3+x/4+x/12)/3]= 56
x- 2x=56
-x = 56
x= -56
hence the number is -56
hope it helps you
according to the question equation so formed is
x - [(x/3+x/4+x/12)/3]= 56
x- 2x=56
-x = 56
x= -56
hence the number is -56
hope it helps you
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