Question

a number is 6 more than the average of its half, it's one third and it's one sixth.Find the number.

Answer 1

if i understood ur question then answer is it........

Answer 2

Answer:

9

Step-by-step explanation:

Let the number be x

So, half of number = $\frac{x}{2}$

One third of number = $\frac{x}{3}$

One sixth of number =  $\frac{x}{6}$

So, the average of its half, it's one third and it's one sixth is:

$\frac{\frac{x}{2}+\frac{x}{3}+\frac{x}{6}}{3}$

$\frac{x}{3}$

Thus the average of its half, it's one third and it's one sixth is $\frac{x}{3}$

Now we are given that a number is 6 more than the average of its half, it's one third and it's one sixth.

$x= \frac{x}{3} +6$

$x- \frac{x}{3}=6$

$\frac{3x-x}{3}=6$

$\frac{2x}{3}=6$

$2x=18$

$x=9$

Hence the number is 9 .