Question

a number is 6 more than the average of its half, its one third, its one sixth,find the number

Answer 1

Let the number be x

We know that,
Half of number = x /2
One third of number = x /3
One sixth of the number = x /6

Average of the half, one - third and one - sixth
=( x /2 + x/3+x /6) /3

= (3x + 2x + x /6)/3

=x /3

According to question,
x -6 = x/3

x - x/3 = 6

2/3 x = 6

x =18/2 = 9

Therefore, The required number is 9

Hope this helps!

:)

Answer 2

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