Question

A number is 64 times the square of its reciprocal the number is

Answer 1

let the no. be x

let the no. be xacc. to que.

let the no. be xacc. to que.x = 64*(1/X)²

let the no. be xacc. to que.x = 64*(1/X)²X=64/x²

let the no. be xacc. to que.x = 64*(1/X)²X=64/x²x*x²=64

let the no. be xacc. to que.x = 64*(1/X)²X=64/x²x*x²=64x³=64

let the no. be xacc. to que.x = 64*(1/X)²X=64/x²x*x²=64x³=64x=∛64

let the no. be xacc. to que.x = 64*(1/X)²X=64/x²x*x²=64x³=64x=∛64x=4

let the no. be xacc. to que.x = 64*(1/X)²X=64/x²x*x²=64x³=64x=∛64x=4therefore the no. is 4

let the no. be xacc. to que.x = 64*(1/X)²X=64/x²x*x²=64x³=64x=∛64x=4therefore the no. is 4