A number is 7cm less than another number. If the sum of their squares
169 find the numbers.
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Let, the numbers be x and y
According to 1st case :
x = y + 7
x - y = 7 ... (1)
According to 2nd case :
x^2 + y^2 = 169 ... (2)
As we know that :
x^2 + y^2 = (x-y)^2 + 2xy
From equation (1) and (2) :
=> 169 = 7^2 + 2xy
=> 169 = 49 + 2xy
=> 2xy = 169 - 49 = 120
=> xy = 60 .... (3)
From equation (1) and (3) :
x - 60/x = 7
=> x^2 - 7x - 60 = 0
=> x^2 - 12x + 5x - 60 = 0
=> x(x - 12) + 5(x - 12) = 0
=> (x - 12)(x + 5) = 0
Required values of x = 12 and -5
Since the negative value is not acceptable so the value of x will be 12
On putting the value of x in equation (1) :
12 - y = 7
=> y = 12 - 7 = 5
So, the numbers will be 12 and 5 ✔✔
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Hope it helps ☺
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