Math, asked by vivekgudipoorigmail, 20 days ago

A number is as much greater than 21 as is less than 71.find the number.

solution:
let the number be x
x+21=71-x
x+x=71-21
2x=50
x=50/2
x=25
so the required number is
x+21=71-x
25+21=71-25
46=46
so,the required number is 46

Answers

Answered by dixitgohel666
0

Answer:

let the number be x

x+21=71-x

x+x=71-21

2x=50

x=50/2

x=25

so the required number is

x+21=71-x

25+21=71-25

46=46

so,the required number is 46

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