A number is choosen at random between 1 and 100. Find the probability that it is divisible by 8.
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Answered by
4
The favourable outcomes are =
12
And the total outcomes =98( as the 1 and 100 should not be counted)
P(E)= 12/98 = 6/49
12
And the total outcomes =98( as the 1 and 100 should not be counted)
P(E)= 12/98 = 6/49
Rushil2405:
Are you sure?
Because people are saying it can be 100 also?
Ok.
u sure it was between and not from?
got deleted, thanks
No problem
My pleasure
Answered by
0
Given:
An integer is chosen between 1 and 100.
Numbers that are divisible by 8 = 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88 and 96.
The rest are not divisible by 8.
Calculation:
The integers are 2, 3, 4, 5, 6,..., 99.
The number of possible outcomes = 98 (Excluding 1 and 100)
Therefore,
Sample space, n(S) = 98.
So,
The possibility of the number divisible by 8, n(E) = 12.
To find probability,
By formula,
P(E) = n(E)/n(S)
=12/98
= 6/49
Hence, P(integer divisible by 8) = 6/49
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