A number is chosen at random from 1 to 25 find the probability of selecting a composite number
Answers
19,20,21,22,23,24,25}
n(S)=25
(A):composite numbers
S(A)={4,6,8,9,10,12,14,15,16,18,20,21,22,24,
25}
n(A)=15
probability of getting composite numbers=n(A)/n(S)
=15/25
=3/5
= 0.6
Probability of selecting a composite number = 0.6
Given:
A number is chosen at random from 1 to 25.
To find:
The probability of selecting a composite number.
Explanation:
Numbers from 1 to 25
Total numbers are 25 so sample size = n(s) = 25
So sample size of composite number from 1 to 25 = n(p)
{4,6,8,9,10,12,14,15,16,18,20,21,22,24,25}
1 is nigher prime nor composite,
n(p) = 15
Probability of selecting a composite number = = = 0.6
Probability of selecting a composite number = 0.6
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