Question

a number is chosen at random from 1 to 50 find the probability of not selecting odd or prime numbers

Answer 1

Answer:

total number of possible outcomes =50

number of possible outcomes=24

probability of not selecting odd or prime numbers

=24/50

=12 /25

therefore the answer is 12/25

Step-by-step explanation:

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Answer 2

Answer:

$\frac{12}{25}$ is the required probability of not selecting odd or prime numbers.

Step-by-step explanation:

Explanation:

Given in the question that, a number is chosen at random from 1 to 50.

Between 1 to 50 there are total 25 even numbers  but 2 is a prime numbers.

So, the numbers which are not odd or prime  are;

4, 6,8,10,12,14,16,18,20,22,24,26,28 , 30 , 32 ,34 , 36 , 38 ,40 ,42 ,44 , 46 , 48 ,50

Step 1:

Total outcome = 50

and favorable outcomes  = 24

Probability (the numbers is not odd or prime) = $\frac{Favorable\ outcomes }{Total \ out \ come }$

P(the numbers is not odd or prime) = $\frac{24}{50}$ = $\frac{12}{25}$.

Final answer:

Hence,$\frac{12}{25}$is  the probability  of not selecting odd or prime  numbers.

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