Question

A number is chosen at random from the numbers -3,-2,-1,0,1,2,3, what will be the probability that the square of this number is less than or equal to 1?

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Answer 1

Answer:

3/7

Explanation:

so 1 square is equal to 1

-1 square is equal to 1

0 square is equal to 0

so these are the only 3 possibilties which is less than or equal to 1

p(e)= no.of outcomes by total no. of outcomes

so ans 3/7

Answer 2

We have -3, -2, -1, 0, 1, 2, 3. (Total 7 numbers)

Out of these 7 numbers we have to select only one number.

All numbers have equal chance for getting selected.

So, the probability for each number to get selected = 1/7

Out of these numbers, -1, 0 and 1 are the numbers whose squares are less than or equal to 1.

Probability = No. of favorable outcomes/Total no. of outcomes

Here, the numbers which satisify the condition in the question (square of the number ≤ 1) are the favorable outcomes. (-1,0 and 1)

Total number of outcomes = 7

Probability for a number whose square is  ≤ 1  = 3/7