Question

A number is chosen at random from the numbers, - 5,-4,-3,-2,-1,0,1,2,3,4,5. Then the probability that square of this number is less than or equal to 1 is

Answer 1

Hey mate ,

P(E) = No. of Favourable Outcomes / Total Number of Outcomes

Favourable outcomes = 1,0,-1

Total number of Favourable outcomes = 3

Total number of outcomes = 11

P(E) = 3/11

Since square of negative number is always positive .

So the favourable outcome will only 3

Hope you find it helpful!!

Do mark it as brainliest!!

Answer 2

Answer: $\frac{3}{11}$

1. Step-by-step explanation:

We have given numbers = -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5

Total outcomes  n(s) = 11

squaring all the numbers we get

25 ,16 ,9 ,4 ,1 ,0 ,1 ,4 ,9 ,16 ,25

Probability;P(E) =$\dfrac{\text { favourable outcomes} }{\text { Total number of outcomes }}$

E: The square of number is less than of equal to 1 = -1, 0, 1

P(E)=$\dfrac{3}{11}$

Hence, The probability is $\dfrac{3}{11}$