A number is chosen from Ist 100 Numbers. find the probability that the number will be divisible by 6.
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→ Numbers divisible by '6' = 6, 12, 18, ... , 96
→ Numbers divisible by '6' = 6 [ 1 , 2 , 3 , 4 ,... , 16 ]
→ Number of no.s satisfying the above CONDITION = 16
► Number of no.s satisfying the sample space { 1 to 100 } = 100
=> Probability of event = n( E ) / n( S ) = 16 / 100 = ( 4 / 25 )
→ Numbers divisible by '6' = 6, 12, 18, ... , 96
→ Numbers divisible by '6' = 6 [ 1 , 2 , 3 , 4 ,... , 16 ]
→ Number of no.s satisfying the above CONDITION = 16
► Number of no.s satisfying the sample space { 1 to 100 } = 100
=> Probability of event = n( E ) / n( S ) = 16 / 100 = ( 4 / 25 )
Answered by
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Hey user!!
TOTAL NO. OF OUTCOMES = 100
THEIRFORE THE POSSIBLE OUTCOMES = THE NUMBERS WHICH ARE DIVISIBLE BY 6
THE POSSIBLE OUTCOMES = 16 ..
THE PROBABILITY= THE POSSIBLE OUTCOMES÷ THE TOTAL NO . OF OUTCOMES.
= 16÷ 100= 0.16..
THEIRFORE,, THR REQURIED PROBABITY= 0.16 ...
HOPE IT HELPS U.
STUDY ON AND KEEP IT UP BRO !!!
FOLLOW ME ..
THANKSS.
TOTAL NO. OF OUTCOMES = 100
THEIRFORE THE POSSIBLE OUTCOMES = THE NUMBERS WHICH ARE DIVISIBLE BY 6
THE POSSIBLE OUTCOMES = 16 ..
THE PROBABILITY= THE POSSIBLE OUTCOMES÷ THE TOTAL NO . OF OUTCOMES.
= 16÷ 100= 0.16..
THEIRFORE,, THR REQURIED PROBABITY= 0.16 ...
HOPE IT HELPS U.
STUDY ON AND KEEP IT UP BRO !!!
FOLLOW ME ..
THANKSS.
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